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Day 242: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    Ray Optics. Asked once: 26 Jun 2022 (same type asked 2 times) See all 2 of this type

    26
    A light ray is incident, at an incident angle θ1\theta_{1}, on the system of two plane mirrors M1M_{1} and M2M_{2} having an inclination angle 75∘75^{\circ} between them (as shown in figure). After reflecting from mirror M1M_{1} it gets reflected back by the mirror M2M_{2} with an angle of reflection 30∘30^{\circ}. The total deviation of the ray will be ____\_\_\_\_ degree.

  2. Question 2

    Waves. Asked once: 29 Jul 2022 (same type asked 2 times) See all 2 of this type

    116
    The speed of a transverse wave passing through a string of length 50 cm50\text{ }cm and mass 10 g10\text{ }g is 60 ms−160{\text{ }ms}^{- 1}. The area of cross-section of the wire is 2.0 mm22.0{\text{ }mm}^{2} and its Young's modulus is 1.2×1011Nm−21.2 \times10^{11}Nm^{- 2}. The extension of the wire over its natural length due to its tension will be x×10−5 mx \times 10^{- 5}\text{ }m. The value of xx is

  3. Question 3

    Current Electricity. Asked once: 8 Apr 2023 (same type asked 2 times) See all 2 of this type

    114
    The number density of free electrons in copper is nearly 8×1028 m−38 \times10^{28}{\text{ }m}^{- 3}. A copper wire has its area of cross section =2×10−6 m2= 2 \times10^{- 6}{\text{ }m}^{2} and is carrying a current of 3.2 A. The drift speed of the electrons is___ ×10−6 ms−1\times10^{- 6}{\text{ }ms}^{- 1}.

  4. Question 4

    Gravitation. Asked once: 26 Jul 2022 (same type asked 2 times) See all 2 of this type

    16
    The percentage decrease in the weight of a rocket, when taken to a height of 32 km32\text{ }km above the surface of earth will, be: (Radius of earth =6400 km= 6400\text{ }km )

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  5. Question 5

    Ray Optics. Asked once: 2021 Paper 22 (same type asked 2 times) See all 2 of this type

    13
    Two plane mirrors M1M_{1} and M2M_{2} are at right angle to each other shown. A point source ' PP ' is placed at ' aa ' and ' 2a2a ' meter away from M1M_{1} and M2M_{2} respectively. The shortest distance between the images thus formed is: (Take 5=2.3)\sqrt{5}= 2.3)

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