PYQ Vault

Day 331: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    Dual Nature of Radiation and Matter. Asked once: 25 Jun 2022 (same type asked 8 times) See all 8 of this type

    106
    A proton, a neutron, an electron and an α\alpha-particle have same energy. If λp,λn,λe\lambda_{p},\lambda_{n},\lambda_{e} and λα\lambda_{\alpha} are the de Broglie's wavelengths of proton, neutron, electron and α\alpha particle respectively, then choose the correct relation from the following:

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  2. Question 2

    Moving Charges and Magnetism. Asked once: 2021 Paper 18 (same type asked 8 times) See all 8 of this type

    1
    The fractional change in the magnetic field intensity at a distance ' rr ' from centre on the axis of current carrying coil of radius ' aa ' to the magnetic field intensity at the centre of the same coil is : (Take r<ar < a )

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  3. Question 3

    Gravitation. Asked once: 30 Jan 2024 (same type asked 8 times) See all 8 of this type

    102
    Escape velocity of a body from earth is 11.2 km/s11.2\text{ }km/s. If the radius of a planet be one-third the radius of earth and mass be one-sixth that of earth, the escape velocity from the planet is:

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  4. Question 4

    Wave Optics. Asked once: 13 Apr 2023 (same type asked 8 times) See all 8 of this type

    109
    In a Young's double slits experiment, the ratio of amplitude of light coming from slits is 2:1. The ratio of the maximum to minimum intensity in the interference pattern is:

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  5. Question 5

    Moving Charges and Magnetism. Asked once: 31 Jan 2023 (same type asked 8 times) See all 8 of this type

    20
    A rod with circular cross-section area 2 cm22{\text{ }cm}^{2} and length 40 cm40\text{ }cm is wound uniformly with 400 turns of an insulated wire. If a current of 0.4 A0.4\text{ }A flows in the wire windings, the total magnetic flux produced inside windings is 4π×10−6 Wb4\pi \times10^{- 6}\text{ }Wb. The relative permeability of the rod is (Given: Permeability of vacuum μ0=4π×10−7NA−2\mu_{0}= 4\pi \times10^{- 7}NA^{- 2} )

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