PYQ Vault
EbooksTutor

Day 392: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    System of Particles and Rotational Motion. Asked once: 1 Feb 2023 (same type asked 5 times) See all 5 of this type

    28
    A solid cylinder is released from rest from the top of an inclined plane of inclination 30∘30^{\circ} and length 60 cm60\text{ }cm. If the cylinder rolls without slipping, its speed upon reaching the bottom of the inclined plane is ____\_\_\_\_ ms−1ms^{- 1}. (Given g=10 ms−2g = 10{\text{ }ms}^{- 2} )

  2. Question 2

    Nuclei. Asked once: 2021 Paper 3 (same type asked 5 times) See all 5 of this type

    12
    Two radioactive substances XX and YY originally have N1N_{1} and N2N_{2} nuclei respectively. Half life of XX is half of the half life of YY. After three half lives of YY, number of nuclei of both are equal. The ratio N1 N2\frac{N_{1}}{{\text{ }N}_{2}} will be equal to:

    Tap an option to check your answer.

  3. Question 3

    Electrostatics. Asked once: 2021 Paper 24 (same type asked 5 times) See all 5 of this type

    1
    A cube is placed inside an electric field, E→=150y2j^\overrightarrow{E}= 150y^{2}\widehat{j}. The side of the cube is 0.5 m0.5\text{ }m and is placed in the field as shown in the given figure. The charge inside the cube is:

    Tap an option to check your answer.

  4. Question 4

    Motion in a Plane. Asked once: 2021 Paper 15 (same type asked 5 times) See all 5 of this type

    7
    If X→\overrightarrow{X} and Y→\overrightarrow{Y} are two vectors, such that ∣X→∣=∣Y→∣&∣X→−Y→∣=10∣X→+Y→∣|\overrightarrow{X}| = |\overrightarrow{Y}|\&|\overrightarrow{X}-\overrightarrow{Y}| = 10|\overrightarrow{X}+\overrightarrow{Y}|, then. Find the angle between X→\overrightarrow{X} and Y→\overrightarrow{Y}

    Tap an option to check your answer.

  5. Question 5

    Semiconductor Electronics. Asked once: 2021 Paper 25 (same type asked 5 times) See all 5 of this type

    7
    LED is constructed from Ga-As-P semiconducting material. The energy gap of this LED is 1.9eV1.9eV. Calculate the wavelength of light emitted and its colour. [h=6.63×10−34Js\left\lbrack h = 6.63 \times10^{- 34}Js \right. and  c=3×108 ms−1]\left. \ c = 3 \times10^{8}{\text{ }ms}^{- 1} \right\rbrack

    Tap an option to check your answer.