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Day 467: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    Nuclei. Asked once: 28 Jan 2025

    12
    Choose the correct nuclear process from the below options [p\left\lbrack p \right. : proton, n : neutron, e−e^{-}: electron, e+e^{+}: positron, vv : neutrino, vˉ\bar{v} : antineutrino]

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  2. Question 2

    Oscillations. Asked once: 29 Jan 2025

    3
    An electric dipole of mass mm, charge qq, and length ll is placed in a uniform electric field E→=E0i^\overrightarrow{E}=E_{0}\widehat{i}. When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be :

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  3. Question 3

    Ray Optics. Asked once: 22 Jan 2026 S1

    14
    A thin convex lens of focal length 5 cm and a thin concave lens of focal length 4 cm are combined together (without any gap) and this combination has magnification m1m_{1} when an object is placed 10 cm before the convex lens. Keeping the positions of convex lens and object undisturbed a gap of 1 cm is introduced between the lenses by moving the concave lens away, which lead to a change in magnification of total lens system to m2m_{2}. The value of ∣m1m2∣\left| \frac{m_{1}}{m_{2}} \right| is ____\_\_\_\_ .

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  4. Question 4

    Semiconductor Electronics. Asked once: 4 Apr 2026 S1

    17
    Consider a circuit consisting of a capacitor (20μ F)(20\mu\text{ }F), resistor ( 100Ω100\Omega ) and two identical diodes as shown in figure. The resistance of diode under forward biasing condition is 10Ω10\Omega. The time constant of the circuit is α×10−3 s\alpha \times10^{- 3}\text{ }s. The value of α\alpha is ____\_\_\_\_ .

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  5. Question 5

    System of Particles and Rotational Motion. Asked once: 2 Apr 2026 S1

    4
    The position of an object having mass 0.1 kg as a function of time tt is given as r→=(10t2i^+5t3j^)m\overrightarrow{r}=\left( 10t^{2}\widehat{i}+ 5t^{3}\widehat{j} \right)m. At t=1 st = 1\text{ }s, which of the following statements are correct? (A) The linear momentum p→=(2i^+1.5j^)kg⋅m/s\overrightarrow{p} = (2\widehat{i} + 1.5\widehat{j})kg \cdot m/s. (B) The force acting on the object F→=(2i^+3j^)N\overrightarrow{F} = (2\widehat{i} + 3\widehat{j})N. (C) The angular momentum of the object about its origin L→=15k^Js\overrightarrow{L} = 15\widehat{k}Js. (D) The torque acting on the object about its origin τ→=20k^Nm\overrightarrow{\tau} = 20\widehat{k}Nm. Choose the correct answer from the option given below.

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