PYQ Vault

Day 588: JEE Mains Physics

5 questions. Try each one first, then open its answer.

  1. Question 1

    Current Electricity. Asked once: 1 Feb 2024

    92
    To measure the temperature coefficient of resistivity α\alpha of a semiconductor, an electrical arrangement shown in the figure is prepared. The arm BCBC is made up of the semiconductor. The experiment is being conducted at 25∘C25^{\circ}C and resistance of the semiconductor arm is 3 mΩ3\text{ }m\Omega. Arm BCBC is cooled at a constant rate of 2∘C/s2^{\circ}C/s. If the galvanometer GG shows no deflection after 10 s, then α\alpha is :

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  2. Question 2

    Electrostatics. Asked once: 27 Jan 2024

    108
    Given below are two statements: one is labelled a Assertion (A) and the other is labelled as Reason(R) Assertion (A): Work done by electric field on moving a positive charge on an equipotential surface is always zero. Reason (R): Electric lines of forces are always perpendicular to equipotential surfaces. In the light of the above statements, choose the most appropriate answer from the options given below:

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  3. Question 3

    Laws of Motion. Asked once: 2021 Paper 26

    10
    An inclined plane making an angle of 30∘30^{\circ} with horizontal is placed in a uniform horizontal electric field 200NC200\frac{N}{C} as shown in the figure. A body of mass 1 kg1\text{ }kg and charge 5mC5mC is allowed to slide down from rest at a height of 1 m1\text{ }m. If the coefficient of friction is 0.2 , find the time taken by the body to reach the bottom.
    [g=9.8 m/s2,sin⁡30∘=12;cos⁡30∘=32]\left\lbrack g= 9.8\text{ }m/s^{2},\sin30^{\circ}=\frac{1}{2};\cos30^{\circ}=\frac{\sqrt{3}}{2} \right\rbrack

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  4. Question 4

    Motion in a Plane. Asked once: 2021 Paper 19

    11
    A bomb is dropped by fighter plane flying horizontally. To an observer sitting in the plane, the trajectory of the bomb is a:

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  5. Question 5

    Motion in a Straight Line. Asked once: 2021 Paper 17

    19
    A particle of mass MM originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation
    F=F0[1−(t−TT)2]F =F_{0}\left\lbrack 1 -\left( \frac{t - T}{T} \right)^{2} \right\rbrack
    Where F0F_{0} and TT are constants. The force acts only for the time interval 2 T2\text{ }T. The velocity vv of the particle after time 2 T2\text{ }T is:

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