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De Broglie wavelength of a gas molecule or electron at a temperature T

This type of question, asked 3 times: 2021 Paper 24, 10 Apr 2023, 23 Jan 2026 S1. All 3 questions below, oldest first.

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  1. Question 1

    2021 Paper 24

    3
    The temperature of an ideal gas in 3-dimensions is 300 K300\text{ }K. The corresponding de-Broglie wavelength of the electron approximately at 300 K300\text{ }K, is: [me=\left\lbrack m_{e}= \right. mass of electron =9×10−31 kg= 9 \times10^{- 31}\text{ }kg h=h = Planck constant =6.6×10−34Js= 6.6 \times10^{- 34}Js kB=k_{B}= Boltzmann constant =1.38×10−23JK−1= 1.38 \times10^{- 23}JK^{- 1} ]

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  2. Question 2

    10 Apr 2023

    18
    The de Broglie wavelength of a molecule in a gas at room temperature (300 K)(300\text{ }K) is λ1\lambda_{1}. If the temperature of the gas is increased to 600 K600\text{ }K, then the de Broglie wavelength of the same gas molecule becomes

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  3. Question 3

    23 Jan 2026 S1

    5
    The de Broglie wavelength of an oxygen molecule at 27∘C27^{\circ}C is x×10−12 mx \times 10^{- 12}\text{ }m. The value of x is (take Planck's constant =6.63×10−34 J.s= 6.63 \times 10^{- 34}\text{ }J.s, Boltzmann constant =1.38×10−23 J/K= 1.38 \times 10^{- 23}\text{ }J/K, mass of oxygen molecule =5.31×10−26 kg= 5.31 \times 10^{- 26}\text{ }kg).

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