PYQs Homework Notes Mocks Board Daily Homework JEE Mains Physics Asked again EM wave along x with E along y of 60 V/m and given wavelength: equation of B The same question, asked 2 times: 28 Jun 2022*, 9 Apr 2024. Every wording below, oldest first.
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Question 1 28 Jun 2022
105 An EM wave propagating in x x x -direction has a wavelength of 8 m m 8\text{ }mm 8 mm . The electric field vibrating in the y-direction has maximum magnitude of 60 V m − 1 60Vm^{- 1} 60 V m − 1 . Choose the correct equations for electric and magnetic fields if the EM wave is propagating in vacuum: A. E y = 60 sin [ π 4 × 10 3 ( x − 3 × 10 8 t ) ] j ^ V m − 1 E_{y} = 60\sin\left\lbrack \frac{\pi}{4} \times 10^{3}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{j}\ Vm^{- 1} E y = 60 sin [ 4 π × 1 0 3 ( x − 3 × 1 0 8 t ) ] j V m − 1 , B z = 2 sin [ π 4 × 10 3 ( x − 3 × 10 8 t ) ] k ^ T B_{z} = 2\sin\left\lbrack \frac{\pi}{4} \times 10^{3}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{k}\ T B z = 2 sin [ 4 π × 1 0 3 ( x − 3 × 1 0 8 t ) ] k T B. E y = 60 sin [ π 4 × 10 3 ( x − 3 × 10 8 t ) ] j ^ V m − 1 E_{y} = 60\sin\left\lbrack \frac{\pi}{4} \times 10^{3}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{j}\ Vm^{- 1} E y = 60 sin [ 4 π × 1 0 3 ( x − 3 × 1 0 8 t ) ] j V m − 1 , B z = 2 × 10 − 7 sin [ π 4 × 10 3 ( x − 3 × 10 8 t ) ] k ^ T B_{z} = 2 \times 10^{- 7}\sin\left\lbrack \frac{\pi}{4} \times 10^{3}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{k}\ T B z = 2 × 1 0 − 7 sin [ 4 π × 1 0 3 ( x − 3 × 1 0 8 t ) ] k T C. E y = 2 × 10 − 7 sin [ π 4 × 10 3 ( x − 3 × 10 8 t ) ] j ^ V m − 1 E_{y} = 2 \times 10^{- 7}\sin\left\lbrack \frac{\pi}{4} \times 10^{3}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{j}\ Vm^{- 1} E y = 2 × 1 0 − 7 sin [ 4 π × 1 0 3 ( x − 3 × 1 0 8 t ) ] j V m − 1 , B z = 60 sin [ π 4 × 10 3 ( x − 3 × 10 8 t ) ] k ^ T B_{z} = 60\sin\left\lbrack \frac{\pi}{4} \times 10^{3}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{k}\ T B z = 60 sin [ 4 π × 1 0 3 ( x − 3 × 1 0 8 t ) ] k T D. E y = 2 × 10 − 7 sin [ π 4 × 10 4 ( x − 4 × 10 8 t ) ] j ^ V m − 1 E_{y} = 2 \times 10^{- 7}\sin\left\lbrack \frac{\pi}{4} \times 10^{4}\left( x - 4 \times 10^{8}t \right) \right\rbrack\widehat{j}\ Vm^{- 1} E y = 2 × 1 0 − 7 sin [ 4 π × 1 0 4 ( x − 4 × 1 0 8 t ) ] j V m − 1 , B z = 60 sin [ π 4 × 10 4 ( x − 4 × 10 8 t ) ] k ^ T B_{z} = 60\sin\left\lbrack \frac{\pi}{4} \times 10^{4}\left( x - 4 \times 10^{8}t \right) \right\rbrack\widehat{k}\ T B z = 60 sin [ 4 π × 1 0 4 ( x − 4 × 1 0 8 t ) ] k T Tap an option to check your answer.
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Question 2 9 Apr 2024
3 A plane EM wave is propagating along x x x direction. It has a wavelength of 4 m m 4\text{ }mm 4 mm . If electric field is in y y y direction with the maximum magnitude of 60 V m − 1 60Vm^{- 1} 60 V m − 1 , the equation for magnetic field is: A. B z = 60 sin [ π 2 ( x − 3 × 10 8 t ) ] k ^ T B_{z} = 60\sin\left\lbrack \frac{\pi}{2}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{k}\ T B z = 60 sin [ 2 π ( x − 3 × 1 0 8 t ) ] k T B. B z = 2 × 10 − 7 sin [ π 2 × 10 3 ( x − 3 × 10 8 t ) ] k ^ T B_{z} = 2 \times 10^{- 7}\sin\left\lbrack \frac{\pi}{2} \times 10^{3}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{k}\ T B z = 2 × 1 0 − 7 sin [ 2 π × 1 0 3 ( x − 3 × 1 0 8 t ) ] k T C. B x = 60 sin [ π 2 ( x − 3 × 10 8 t ) ] i ^ T B_{x} = 60\sin\left\lbrack \frac{\pi}{2}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{i}T B x = 60 sin [ 2 π ( x − 3 × 1 0 8 t ) ] i T D. B z = 2 × 10 − 7 sin [ π 2 ( x − 3 × 10 8 t ) ] k ^ T B_{z} = 2 \times 10^{- 7}\sin\left\lbrack \frac{\pi}{2}\left( x - 3 \times 10^{8}t \right) \right\rbrack\widehat{k}T B z = 2 × 1 0 − 7 sin [ 2 π ( x − 3 × 1 0 8 t ) ] k T Tap an option to check your answer.
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