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Dielectric slab of thickness 3d/4 inserted in a parallel plate capacitor: new capacitance

The same question, asked 2 times: 2021 Paper 5, 28 Jul 2022. Every wording below, oldest first.

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  1. Question 1

    2021 Paper 5

    2
    For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant KK is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 34 d\frac{3}{4}\text{ }d, where ' dd ' is the separation between the plates of parallel plate capacitor. The new capacitance ( C′C^{'} ) in terms of original capacitance (C0)\left( C_{0} \right) is given by the following relation :

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  2. Question 2

    28 Jul 2022

    99
    A slab of dielectric constant KK has the same crosssectional area as the plates of a parallel plate capacitor and thickness 34 d\frac{3}{4}\text{ }d, where dd is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be: (Given Co=C_{o}= capacitance of capacitor with air as medium between plates.)

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