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Capacitor filled with a material of given resistivity: leakage current or resistance (RC = resistivity x permittivity)

This type of question, asked 2 times: 2021 Paper 18, 8 Apr 2026 S2. All 2 questions below, oldest first.

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  1. Question 1

    2021 Paper 18

    19
    The material filled between the plates of a parallel plate capacitor has resistivity 200Ωm200\Omega m. The value of capacitance of the capacitor is 2pF2pF. If a potential difference of 40 V40\text{ }V is applied across the plates of the capacitor, then the value of leakage current flowing out of the capacitor is : (given the value of relative permitivity of material is 50 )

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  2. Question 2

    8 Apr 2026 S2

    21
    A parallel plate capacitor is having separation between plates 0.885 mm . It has a capacitance of 1μ F1\mu\text{ }F when the space between the plates is filled with an insulating material of resistivity 1×1013Ω m1 \times 10^{13}\Omega\text{ }m and resistance 17.7×1014Ω17.7 \times 10^{14}\Omega. Relative permittivity of the insulating material is α×107\alpha \times 10^{7}. The value of α\alpha is ____\_\_\_\_ . (Take permittivity of free space =8.85×10−12 F/m= 8.85 \times 10^{- 12}\text{ }F/m)