PYQ Vault

Capacitance with a dielectric slab or metal sheet thinner than the plate gap

This type of question, asked 9 times: 2021 Paper 5, 25 Jun 2022, 28 Jul 2022, 25 Jan 2023, 6 Apr 2023, 10 Apr 2023, 8 Apr 2024, 21 Jan 2026 S1, 23 Jan 2026 S2. All 10 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2021 Paper 5

    2
    For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant KK is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is 34 d\frac{3}{4}\text{ }d, where ' dd ' is the separation between the plates of parallel plate capacitor. The new capacitance ( C′C^{'} ) in terms of original capacitance (C0)\left( C_{0} \right) is given by the following relation :

    Tap an option to check your answer.

  2. Question 2

    25 Jun 2022

    98
    Two metallic plates form a parallel plate capacitor. The distance between the plates is ' dd '. A metal sheet of thickness d2\frac{d}{2} and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

    Tap an option to check your answer.

  3. Question 3

    28 Jul 2022

    99
    A slab of dielectric constant KK has the same crosssectional area as the plates of a parallel plate capacitor and thickness 34 d\frac{3}{4}\text{ }d, where dd is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be: (Given Co=C_{o}= capacitance of capacitor with air as medium between plates.)

    Tap an option to check your answer.

  4. Question 4

    25 Jan 2023

    16
    A parallel plate capacitor has plate area 40 cm240{\text{ }cm}^{2} and plates separation 2 mm2\text{ }mm. The space between the plates is filled with a dielectric medium of a thickness 1 mm1\text{ }mm and dielectric constant 5. The capacitance of the system is:

    Tap an option to check your answer.

  5. Question 5

    25 Jan 2023

    119
    A capacitor has capacitance 5μF5\mu F when its parallel plates are separated by air medium of thickness dd. A slab of material of dielectric constant 1.5 having area equal to that of plates but thickness d2\frac{d}{2} is inserted between the plates. Capacitance of the capacitor in the presence of slab will be ___ μF\mu F.
  6. Question 6

    6 Apr 2023

    30
    A parallel plate capacitor with plate area AA and plate separation dd is filled with a dielectric material of dielectric constant K=4K = 4. The thickness of the dielectric material is xx, where x<dx < d. Let C1C_{1} and C2C_{2} be the capacitance of the system for x=13 dx =\frac{1}{3}\text{ }d and x=2 d3x =\frac{2\text{ }d}{3}, respectively. If C1=2μFC_{1}= 2\mu F the value of C2C_{2} is___ μF\mu F
  7. Question 7

    10 Apr 2023

    96
    The distance between two plates of a capacitor is dd and its capacitance is C1C_{1}, when air is the medium between the plates. If a metal sheet of thickness 2 d3\frac{2\text{ }d}{3} and of same area as plate is introduced between the plates, the capacitance of the capacitor becomes C2C_{2}. The ratio C2C1\frac{C_{2}}{C_{1}} is:

    Tap an option to check your answer.

  8. Question 8

    8 Apr 2024

    103
    A capacitor has air as dielectric medium and two conducting plates of area 12 cm212{\text{ }cm}^{2} and they are 0.6 cm0.6\text{ }cm apart. When a slab of dielectric having area 12 cm212{\text{ }cm}^{2} and 0.6 cm0.6\text{ }cm thickness is inserted between the plates, one of the conducting plates has to be moved by 0.2 cm0.2\text{ }cm to keep the capacitance same as in previous case. The dielectric constant of the slab is : (Given ϵ0=8.834×10−12 F/m\epsilon_{0}= 8.834 \times10^{- 12}\text{ }F/m )

    Tap an option to check your answer.

  9. Question 9

    21 Jan 2026 S1

    9
    A parallel plate capacitor has capacitance C, when there is vacuum within the parallel plates. A sheet having thickness (13)rd \left( \frac{1}{3} \right)^{\text{rd~}} of the separation between the plates and relative permittivity K is introduced between the plates. The new capacitance of the system is :

    Tap an option to check your answer.

  10. Question 10

    23 Jan 2026 S2

    9
    A parallel plate capacitor with plate separation 5 mm is charged by a battery. On introducing a mica sheet of 2 mm and maintaining the connections of the plates with the terminals of the battery, it is found that it draws 25%25\% more charge from the battery. The dielectric constant of mica is ____\_\_\_\_ .

    Tap an option to check your answer.