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Average kinetic energy of gas molecules at a temperature (3/2 kT)

This type of question, asked 6 times: 2021 Paper 13, 2021 Paper 24, 1 Feb 2023, 27 Jan 2024, 31 Jan 2024, 28 Jan 2025. All 6 questions below, oldest first.

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  1. Question 1

    2021 Paper 13

    11
    Find average kinetic energy of a monatomic gas molecule, assuming ideal behaviour. (Given TT is the temperature of the gas and kk is Boltzmann constant)

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  2. Question 2

    2021 Paper 24

    25
    The average translational kinetic energy of N2N_{2} gas molecules at ____\_\_\_\_ ∘C^{\circ}C becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1 volt. (Given kB=1.38×10−23 J/Kk_{B}= 1.38 \times10^{- 23}\text{ }J/K ) (Fill the nearest integer).

  3. Question 3

    1 Feb 2023

    20
    The average kinetic energy of a molecule of the gas is

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  4. Question 4

    27 Jan 2024

    20
    The average kinetic energy of a monatomic molecule is 0.414eV0.414eV at temperature: (Use KB=1.38×10−23 J/KK_{B} = 1.38 \times 10^{- 23}\text{ }J/K)

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  5. Question 5

    31 Jan 2024

    1
    The parameter that remains the same for molecules of all gases at a given temperature is:

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  6. Question 6

    28 Jan 2025

    80
    The kinetic energy of translation of the molecules in 50 g of CO2CO_{2} gas at 17∘C17^{\circ}C is :

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