PYQ Vault
EbooksTutor

Velocity at the instant acceleration becomes zero, for a cubic position-time relation

This type of question, asked 2 times: 29 Jan 2024, 1 Feb 2024. All 2 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    29 Jan 2024

    107
    A particle is moving in a straight line. The variation of position ' xx ' as a function of time ' tt ' is given as x=(t3−6t2+20t+15)mx =\left( t^{3}- 6t^{2}+ 20t + 15 \right)m. The velocity of the body when its acceleration becomes zero is :

    Tap an option to check your answer.

  2. Question 2

    1 Feb 2024

    30
    A particle is moving in one dimension (along xx axis) under the action of a variable force. It's initial position was 16 m16\text{ }m right of origin. The variation of its position (x)(x) with time (t)(t) is given as x=−3t3+18t2+16tx = - 3t^{3}+ 18t^{2}+ 16t, where xx is in mm and tt is in ss. The velocity of the particle when its acceleration becomes zero is_____ m/sm/s.