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Cyclotron: kinetic energy gained or number of revolutions

This type of question, asked 2 times: 2021 Paper 19, 27 Jul 2022. All 2 questions below, oldest first.

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  1. Question 1

    2021 Paper 19

    23
    If the maximum value of accelerating potential provided by a radio frequency oscillator is 12kV12kV. The number of revolution made by a proton in a cyclotron to achieve one sixth of the speed of light is [mp=1.67×10−27 kg,e=1.6×10−19C,\left\lbrack m_{p}= 1.67 \times10^{- 27}\text{ }kg,e = 1.6 \times10^{- 19}C, \right. Speed of light =3×108 m/s= 3 \times10^{8}\text{ }m/s ]
  2. Question 2

    27 Jul 2022

    103
    A cyclotron is used to accelerate protons. If the operating magnetic field is 1.0 T1.0\text{ }T and the radius of the cyclotron 'dees' is 60 cm60\text{ }cm, the kinetic energy of the accelerated protons in MeVMeV will be: [use mp=1.6×10−27 kg,e=1.6×10−19Cm_{p}= 1.6 \times10^{- 27}\text{ }kg,e = 1.6 \times10^{- 19}C ]

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