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Torque on a current loop in a uniform field

This type of question, asked 3 times: 2021 Paper 19, 4 Apr 2026 S2, 8 Apr 2026 S2. All 3 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2021 Paper 19

    27
    A coil in the shape of an equilateral triangle of side 10 cm10\text{ }cm lies in a vertical plane between the pole pieces of permanent magnet producing a horizontal magnetic field 20mT20mT. The torque acting on the coil when a current of 0.2 A0.2\text{ }A is passed through it and its plane becomes parallel to the magnetic field will be x×10−5Nm\sqrt{x}\times10^{- 5}Nm. The value of xx is

  2. Question 2

    4 Apr 2026 S2

    24
    A circular coil of radius 2 cm and 125 turns carries a current of 1 A . The coil is placed in a uniform magnetic field of magnitude 0.4 T . The axis of the coil makes an angle of 30∘30^{\circ} with the direction of the magnetic field. The torque acting on the coil is α×10−4 N.m\alpha \times 10^{- 4}\text{ }N.m. The value of α\alpha is ____\_\_\_\_ . ( π=3.14\pi = 3.14 )

  3. Question 3

    8 Apr 2026 S2

    14
    A current carrying circular loop of radius 2 cm with unit normal n^=k^+i^2\widehat{n}=\frac{\widehat{k}+\widehat{i}}{\sqrt{2}} is placed in a magnetic field, B→=B0(3i^+2k^)\overrightarrow{B}=B_{0}(3\widehat{i}+ 2\widehat{k}). If B0=4×10−3 TB_{0}= 4 \times10^{- 3}\text{ }T and current =1002 A= 100\sqrt{2}\text{ }A, the torque experienced by the loop is ____\_\_\_\_ Wb.A. (π=3.14)(\pi= 3.14)

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