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Q value of the alpha decay of uranium-238 into thorium-234 from atomic masses

The same question, asked 2 times: 12 Apr 2023*, 13 Apr 2023. Every wording below, oldest first.

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  1. Question 1

    12 Apr 2023

    26
    A common example of alpha decay is
     92238U⟶ 90234Th+ 2He4+Q\ _{92}^{238}U \longrightarrow\ _{90}^{234}Th +\ _{2}He^{4}+ Q
    Given:  92238U=238.05060u\ _{92}^{238}U = 238.05060u,  90234Th=234.04360u\ _{90}^{234}Th = 234.04360u,  24He=4.00260u\ _{2}^{4}He = 4.00260u, and
    1u=931.5MeVc21u = 931.5\frac{MeV}{c^{2}}
    The energy released (Q) during the alpha decay of  92238U\ _{92}^{238}U is__ MeVMeV

  2. Question 2

    13 Apr 2023

    20
     92238 A→ 90234 B+ 24D+Q\ _{92}^{238}\text{ }A \rightarrow\ _{90}^{234}\text{ }B +\ _{2}^{4}D + Q In the given nuclear reaction, the approximate amount of energy released will be : [Given, mass of  92238 A=238.05079×931.5MeV/c2\ _{92}^{238}\text{ }A = 238.05079 \times 931.5MeV/c^{2}, mass of  90234 B=234.04363×931.5MeV/c2\ _{90}^{234}\text{ }B = 234.04363 \times 931.5MeV/c^{2}, mass of  24D=4.00260×931.5MeV/c2\ _{2}^{4}D = 4.00260 \times 931.5MeV/c^{2} ]

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