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Energy released when three helium nuclei form a carbon nucleus

This type of question, asked 2 times: 5 Apr 2024, 9 Apr 2024. All 2 questions below, oldest first.

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  1. Question 1

    5 Apr 2024

    27
    If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is _____ ×10−2MeV\times10^{- 2}MeV. (Given 1u=931MeV/c21u = 931MeV/c^{2}, atomic mass of helium =4.002603u= 4.002603u )

  2. Question 2

    9 Apr 2024

    23
    A star has 100%100\% helium composition. It starts to convert three  4He\ ^{4}He into one  12C\ ^{12}C via triple alpha process as  4He+ 4He+ 4He→ 12C+Q\ ^{4}He +\ ^{4}He +\ ^{4}He \rightarrow\ ^{12}C + Q. The mass of the star is 2.0×1032 kg2.0 \times10^{32}\text{ }kg and it generates energy at the rate of 5.808×1030 W5.808 \times10^{30}\text{ }W. The rate of converting these  4He\ ^{4}He to  12C\ ^{12}C is n×1042 s−1n \times10^{42}{\text{ }s}^{- 1}, where nn is ________ . [Take, mass of  4He=4.0026u\ ^{4}He = 4.0026u, mass of  12C=12u\ ^{12}C = 12u ]