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16 ohm wire bent into a square with a 9 V cell (1 ohm) across one side: voltage across a diagonal (or energy in a capacitor there)

The same question, asked 2 times: 2021 Paper 15*, 29 Jan 2024. Every wording below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2021 Paper 15

    9
    A wire of 16Ω16\Omega is bent to form a square. Now a cell of 9 volt and internal resistance 1Ω1\Omega is connected across one of the sides. Find the potential difference across the diagram of the square.

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  2. Question 2

    29 Jan 2024

    27
    A 16Ω16\Omega wire is bend to form a square loop. A 9 V9\text{ }V battery with internal resistance 1Ω1\Omega is connected across one of its sides. If a 4μF4\mu F capacitor is connected across one of its diagonals, the energy stored by the capacitor will be x2μJ\frac{x}{2}\mu J. where x=x = _______