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Length of a seconds pendulum at a height of 2R above the earth

The same question, asked 2 times: 25 Jul 2022, 1 Feb 2024. Every wording below, oldest first.

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  1. Question 1

    25 Jul 2022

    103
    The length of a seconds pendulum at a height h=2Rh = 2R from earth surface will be: (Given: R=R = Radius of earth and acceleration due to gravity at the surface of earth g=π2 m/s−2g =\pi^{2}\text{ }m/s^{- 2} )

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  2. Question 2

    1 Feb 2024

    2
    If RR is the radius of the earth and the acceleration due to gravity on the surface of earth is g=π2 m/s2g=\pi^{2}\text{ }m/s^{2}, then the length of the second's pendulum at a height h=2Rh= 2R from the surface of earth will be,

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