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Velocity at a given time from the SHM equation

This type of question, asked 2 times: 27 Jun 2022, 4 Apr 2024. All 2 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    27 Jun 2022

    100
    The equation of a particle executing simple harmonic motion is given by x=sin⁡π(t+13)mx = \sin\pi\left( t +\frac{1}{3} \right)m. At t=1 st = 1\text{ }s, the speed of particle will be ____\_\_\_\_ cm s−1cm\ s^{- 1} (Given: π=3.14\pi = 3.14 )

  2. Question 2

    4 Apr 2024

    111
    The displacement of a particle executing SHM is given by x=10sin⁡(ωt+π3)mx = 10\sin\left( \omega t +\frac{\pi}{3} \right)m. The time period of motion is 3.14 s3.14\text{ }s. The velocity of the particle at t=0t = 0 is ______ m/sm/s.