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Angular momentum of a projectile about the point of projection

This type of question, asked 4 times: 29 Jan 2023, 30 Jan 2024, 31 Jan 2024, 24 Jan 2025. All 4 questions below, oldest first.

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  1. Question 1

    29 Jan 2023

    111
    A particle of mass 100 g100\text{ }g is projected at time t=0t = 0 with a speed 20 ms−120{\text{ }ms}^{- 1} at an angle 45∘45^{\circ} to the horizontal as given in the figure. The magnitude of the angular momentum of the particle about the starting point at time t=2 st = 2\text{ }s is found to be Kkgm2s\frac{\sqrt{K}kgm^{2}}{s}. The value of KK is (Take  g=10 ms−2)\left. \ g = 10{\text{ }ms}^{- 2} \right)

  2. Question 2

    30 Jan 2024

    18
    A particle of mass mm projected with a velocity ' uu ' making an angle of 30∘30^{\circ} with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height hh is :

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  3. Question 3

    31 Jan 2024

    115
    A body of mass ' mm ' is projected with a speed ' uu ' making an angle of 45∘45^{\circ} with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as 2mu3Xg\frac{\sqrt{2}mu^{3}}{Xg}. The value of ' XX ' is _____

  4. Question 4

    24 Jan 2025

    8
    An object of mass ' mm ' is projected from origin in a vertical xy plane at an angle 45∘45^{\circ} with the x -axis with an initial velocity v0v_{0}. The magnitude and direction of the angular momentum of the object with respect to origin, when it reaches at the maximum height, will be [ g is acceleration due to gravity]

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