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Angular momentum of a particle from its position and velocity, or moving along a straight line

This type of question, asked 3 times: 28 Jun 2022, 29 Jan 2024, 21 Jan 2026 S2. All 3 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    28 Jun 2022

    25
    The position vector of 1 kg1\text{ }kg object is r→=(3i^−j^)m\overrightarrow{r}= (3\widehat{i}-\widehat{j})m and its velocity v→=(3j^+k^)ms−1\overrightarrow{v}= (3\widehat{j}+\widehat{k})ms^{- 1}. The magnitude of its angular momentum is x kg m2s−1\sqrt{x}\ kg\ m^{2}s^{- 1} where xx is

  2. Question 2

    29 Jan 2024

    120
    A body of mass 5 kg5\text{ }kg moving with a uniform speed 32 ms−13\sqrt{2}{\text{ }ms}^{- 1} in X−YX - Y plane along the line y=x+4y = x + 4. The angular momentum of the particle about the origin will be _____ kg m2s−1kg\ m^{2}s^{- 1}.

  3. Question 3

    21 Jan 2026 S2

    6
    Two cars A and B each of mass 103 kg10^{3}\text{ }kg are moving on parallel tracks separated by a distance of 10 m , in same direction with speeds 72 km/h72\text{ }km/h and 36 km/h36\text{ }km/h. The magnitude of angular momentum of car A with respect to car B is ____\_\_\_\_ J.s.

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