PYQ Vault
EbooksTutor

Comparing moments of inertia of standard bodies of the same mass and radius

This type of question, asked 3 times: 2021 Paper 1, 25 Jun 2022, 28 Jan 2025. All 3 questions below, oldest first.

Try each one first, then open its answer.

  1. Question 1

    2021 Paper 1

    14
    Moment of inertia (M.I.) of four bodies, having same mass and radius, are reported as I1=I_{1}= M.I. of thin circular ring about its diameter, I2=I_{2}= M.I. of circular disc about an axis perpendicular to disc and going through the centre, I3=I_{3}= M.I. of solid cylinder about its axis and I4=I_{4}= M.I. of solid sphere about its diameter. Then :-

    Tap an option to check your answer.

  2. Question 2

    25 Jun 2022

    114
    Moment of Inertia (M.I.) of four bodies having same mass ' MM ' and radius ' 2R2R ' are as follows: I1=I_{1}= M.I. of solid sphere about its diameter I2=I_{2}= M.I. of solid cylinder about its axis I3=I_{3}= M.I. of solid circular disc about its diameter I4=I_{4}= M.I. of thin circular ring about its diameter If 2(I2+I3)+I4=x2\left( I_{2}+I_{3} \right)+I_{4}=x. I1I_{1} then the value of xx will be

  3. Question 3

    28 Jan 2025

    22
    The moment of inertia of a solid disc rotating along its diameter is 2.5 times higher than the moment of inertia of a ring rotating in similar way. The moment of inertia of a solid sphere which has same radius as the disc and rotating in similar way, is n times higher than the moment of inertia of the given ring. Here, n=n =  _____\ \_\_\_\_\_ Consider all the bodies have equal masses.