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Torque of a force from its position and force vectors

This type of question, asked 5 times: 25 Jun 2022, 29 Jul 2022, 10 Apr 2023, 22 Jan 2025, 29 Jan 2025. All 5 questions below, oldest first.

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  1. Question 1

    25 Jun 2022

    4
    If force F→=3i^+4j^−2k^\overrightarrow{F}= 3\widehat{i}+ 4\widehat{j}- 2\widehat{k} acts on a particle having position vector 2i^+j^+2k^2\widehat{i}+\widehat{j}+ 2\widehat{k} then, the torque about the origin will be:-

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  2. Question 2

    29 Jul 2022

    106
    The torque of a force 5i^+3j^−7k^5\widehat{i}+ 3\widehat{j}- 7\widehat{k} about the origin is τ\tau. If the force acts on a particle whose position vector is 2i^+2j^+k^2\widehat{i}+ 2\widehat{j}+\widehat{k}, then the value of τ\tau will be :

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  3. Question 3

    10 Apr 2023

    118
    A force of −Pk^- P\widehat{k} acts on the origin of the coordinate system. The torque about the point (2,−3)(2, - 3) is P(ai^+bj^)P(a\widehat{i}+ b\widehat{j}), the ratio of ab\frac{a}{b} is x2\frac{x}{2}. The value of xx is

  4. Question 4

    22 Jan 2025

    87
    The torque due to the force (2i^+j^+2k^)(2\widehat{i}+\widehat{j}+ 2\widehat{k}) about the origin, acting on a particle whose position vector is (i^+j^+k^)(\widehat{i}+\widehat{j}+\widehat{k}), would be

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  5. Question 5

    29 Jan 2025

    21
    The coordinates of a particle with respect to origin in a given reference frame is (1,1,1)(1,1,1) meters. If a force of F→=i^−j^+k^\overrightarrow{F}=\widehat{i}-\widehat{j}+\widehat{k} acts on the particle, then the magnitude of torque (with respect to origin) in zz-direction is _____\_\_\_\_\_