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Ice mixed with water or a hot body: how much ice melts or the final state

This type of question, asked 4 times: 25 Jun 2022, 25 Jul 2022, 29 Jan 2023, 28 Jan 2026 S1. All 4 questions below, oldest first.

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  1. Question 1

    25 Jun 2022

    95
    A copper block of mass 5.0 kg5.0\text{ }kg is heated to a temperature of 500∘C500^{\circ}C and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper: 0.39Jg−1 ∘C−10.39Jg^{- 1}\ ^{\circ}C^{- 1} and latent heat of fusion of water : 335 J g−1335\text{ }J{\text{ }g}^{- 1} ]

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  2. Question 2

    25 Jul 2022

    113
    A block of ice of mass 120 g120\text{ }g at temperature 0∘C0^{\circ}C is put in 300gm300gm of water at 25∘C25^{\circ}C. The xgxg of ice melts as the temperature of the water reaches 0∘C0^{\circ}C. The value of xx is ____\_\_\_\_. [Use: Specific heat capacity of water =4200= 4200 Jkg−1 K−1Jkg^{- 1}{\text{ }K}^{- 1}, Latent heat of ice =3.5×105Jkg−1= 3.5 \times10^{5}Jkg^{- 1}]

  3. Question 3

    29 Jan 2023

    94
    Heat energy of 184 kJ184\text{ }kJ is given to ice of mass 600 g600\text{ }g at −12∘C-12^{\circ}C. Specific heat of ice is 2222.3 J kg−1C−12222.3\text{ }J{\text{ }kg}^{- 1}C^{- 1} and latent heat of ice is 336kJkg−1336kJkg^{- 1} A. Final temperature of system will be 0∘C0^{\circ}C. B. Final temperature of the system will be greater than 0∘C0^{\circ}C. C. The final system will have a mixture of ice and water in the ratio of 5:1. D. The final system will have a mixture of ice and water in the ratio of 1:5. E. The final system will have water only. Choose the correct answer from the options given below:

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  4. Question 4

    28 Jan 2026 S1

    1
    10 kg of ice at −10∘C-10^{\circ}C is added to 100 kg of water to lower its temperature from 25∘C25^{\circ}C. Consider no heat exchange to surroundings. The decrement to the temperature of water is ____\_\_\_\_  ∘C\ ^{\circ}C. (specific heat of ice =2100 J/Kg. ∘C= 2100\text{ }J/Kg.\ ^{\circ}C, specific heat of water =4200 J/Kg. ∘C= 4200\text{ }J/Kg.\ ^{\circ}C, latent heat of fusion of ice =3.36×105 J/Kg= 3.36 \times10^{5}\text{ }J/Kg )

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