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Error in the equivalent resistance of two resistors in parallel

This type of question, asked 2 times: 2021 Paper 24, 6 Apr 2023. All 2 questions below, oldest first.

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  1. Question 1

    2021 Paper 24

    9
    Two resistors R1=(4±0.8)ΩR_{1}= (4 \pm 0.8)\Omega and R2=(4±0.4)ΩR_{2}=\left( 4 \pm 0.4 \right)\Omega are connected in parallel. The equivalent resistance of their parallel combination will be:

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  2. Question 2

    6 Apr 2023

    10
    Two resistances are given as R1=(10±0.5)ΩR_{1}= (10 \pm 0.5)\Omega and R2=(15±0.5)ΩR_{2}= (15 \pm 0.5)\Omega. The percentage error in the measurement of equivalent resistance when they are connected in parallel is

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