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Slit width so that a given number of double-slit maxima fit in the single-slit central maximum

This type of question, asked 2 times: 8 Apr 2024, 4 Apr 2025. All 2 questions below, oldest first.

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  1. Question 1

    8 Apr 2024

    116
    Two slits are 1 mm1\text{ }mm apart and the screen is located 1 m1\text{ }m away from the slits. A light wavelength 500 nm500\text{ }nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is ………..×10−4 m\ldots\ldots\ldots.. \times10^{- 4}\text{ }m.
  2. Question 2

    4 Apr 2025

    99
    In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen from slits is 2 m and the wavelength of the source is 400 nm . If the 20 maxima of the double slit pattern are contained within the centre maximum of the single slit diffraction pattern, then the width of each slit is x×10−3 cmx \times 10^{- 3}\text{ }cm, where x -value is