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Work done by a position-dependent force in a plane between two points

This type of question, asked 2 times: 14 Jun 2022, 23 Jan 2025. All 2 questions below, oldest first.

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  1. Question 1

    14 Jun 2022

    9
    A particle experiences a variable force F→=(4xi^+3y2j^)\overrightarrow{F}=\left( 4x\widehat{i}+ 3y^{2}\widehat{j} \right) in a horizontal x−yx - y plane. Assume distance in meters and force is newton. If the particle moves from point (1,2)(1,2) to point (2,3)(2,3) in the x−yx - y plane, the Kinetic Energy changes by

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  2. Question 2

    23 Jan 2025

    24
    A force f=x2yi^+y2j^f =x^{2}y\widehat{i}+y^{2}\widehat{j} acts on a particle in a plane x+y=10x + y = 10. The work done by this force during a displacement from (0,0)(0,0) to (4 m,2 m)(4\text{ }m,2\text{ }m) is ______\_\_\_\_\_\_ Joule (round off to the nearest integer)