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Potentiometer: internal resistance of a cell shunted by two different resistances

This type of question, asked 4 times: 27 Jun 2022, 29 Jan 2023, 4 Apr 2024, 28 Jan 2026 S1. All 4 questions below, oldest first.

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  1. Question 1

    27 Jun 2022

    25
    A cell, shunted by a 8Ω8\Omega resistance, is balanced across a potentiometer wire of length 3 m3\text{ }m. The balancing length is 2 m2\text{ }m when the cell is shunted by 4Ω4\Omega resistance. The value of internal resistance of the cell will be ____\_\_\_\_ Ω\Omega.

  2. Question 2

    29 Jan 2023

    118
    A null point is found at 200 cm200\text{ }cm in potentiometer when cell in secondary circuit is shunted by 5Ω5\Omega. When a resistance of 15Ω15\Omega is used for shunting, null point moves to 300 cm300\text{ }cm. The internal resistance of the cell is_____ Ω\Omega.

  3. Question 3

    4 Apr 2024

    15
    To measure the internal resistance of a battery, potentiometer is used. For R=10ΩR = 10\Omega, the balance point is observed at l=500 cm\mathcal{l =}500\text{ }cm and for R=1ΩR = 1\Omega the balance point is observed at l=400 cm\mathcal{l =}400\text{ }cm. The internal resistance of the battery is approximately:

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  4. Question 4

    28 Jan 2026 S1

    3
    In the potentiometer, when the cell in the secondary circuit is shunted with 4Ω4\Omega resistance, the balance is obtained at the length 120 cm of wire. Now when the same cell in shunted with 12Ω12\Omega resistance, the balance is shifted to a length of 180 cm . The internal resistance of cell is ____\_\_\_\_ Ω\Omega.

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