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Stopping potential at wavelength lambda and at a multiple of lambda: threshold wavelength

The same question, asked 3 times: 11 Apr 2023*, 31 Jan 2024*, 2 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    11 Apr 2023

    12
    A metallic surface is illuminated with radiation of wavelength λ\lambda, the stopping potential is VoV_{o}. If the same surface is illuminated with radiation of wavelength 2λ2\lambda, the stopping potential becomes V04\frac{V_{0}}{4}. The threshold wavelength for this metallic surface will be -

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  2. Question 2

    31 Jan 2024

    20
    When a metal surface is illuminated by light of wavelength λ\lambda, the stopping potential is 8 V8\text{ }V. When the same surface is illuminated by light of wavelength 3λ3\lambda, stopping potential is 2 V2\text{ }V. The threshold wavelength for this surface is:

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  3. Question 3

    2 Apr 2026 S1

    17
    For a certain metal, when monochromatic light of wavelength λ\lambda is incident, the stopping potential for photoelectrons is 3V03V_{0}. When the same metal is illuminated by light of wavelength 2λ2\lambda, then the stopping potential becomes V0V_{0}. The threshold wavelength for photoelectric emission for the given metal is αλ\alpha\lambda. The value of α\alpha is ____\_\_\_\_ .

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