Ratio of de Broglie wavelengths of particles accelerated through potential differences
This type of question, asked 8 times: 2021 Paper 3, 2021 Paper 6, 2021 Paper 14, 25 Jul 2022, 29 Jul 2022, 29 Jan 2023, 12 Apr 2023, 4 Apr 2026 S2. All 8 questions below, oldest first.
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Question 1
2021 Paper 3
16An particle and a proton are accelerated from rest by a potential difference of . After this, their de Broglie wavelengths are and respectively. The ratio is:Tap an option to check your answer.
Question 2
2021 Paper 6
7The de-Broglie wavelength associated with an electron and a proton were calculated by accelerating them through the same potential of . What should nearly be the ratio of their wavelengths?Tap an option to check your answer.
Question 3
2021 Paper 14
1An electron, a proton and an -particle are accelerated from rest through the same potential difference. Arrange their de Broglie wavelengths in decreasing order.Tap an option to check your answer.
Question 4
25 Jul 2022
97The ratio of wavelengths of proton and deuteron accelerated by potential and is . Then, the ratio of to will beTap an option to check your answer.
Question 5
29 Jul 2022
100An particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particles will be:Tap an option to check your answer.
Question 6
29 Jan 2023
104The ratio of de-Broglie wavelength of an particle and a proton accelerated from rest by the same potential is , the value of is-Tap an option to check your answer.
Question 7
12 Apr 2023
6A proton and an -particle are accelerated from rest by and potentials, respectively. The ratio of their de-Broglie wavelength is:Tap an option to check your answer.
Question 8
4 Apr 2026 S2
19The de Broglie wavelength associated with an electron accelerated through a potential difference V is and the de Broglie wavelength associated with a proton accelerated through the same potential difference is . If their corresponding masses are and , respectively, then the ratio of their de Broglie wavelengths is .Tap an option to check your answer.