PYQ Vault

Oscillations

JEE Mains Physics. Try each one first, then open its answer.

Top 10 JEE Mains PYQs to practise first

The questions and kinds of question asked most often come first. Each one says how often and in which papers.

  1. Question 1

    This type asked 7 times: 2021 Paper 12, 2021 Paper 17, 2021 Paper 26, 30 Jan 2023, 27 Jan 2024, 9 Apr 2024, 4 Apr 2026 S1. This one: 4 Apr 2026 S1 See all 7 of this type

    23
    The velocity of a particle executing simple harmonic motion along x -axis is described as v2=50−x2v^{2} = 50 - x^{2}, where x represents displacement. If the time period of motion is x7s\frac{x}{7}s, the value of xx is ____\_\_\_\_ .
  2. Question 2

    This type asked 7 times: 2021 Paper 7, 2021 Paper 16, 31 Jan 2023, 1 Feb 2023, 12 Apr 2023, 13 Apr 2023, 29 Jan 2024. This one: 29 Jan 2024 See all 7 of this type

    28
    When the displacement of a simple harmonic oscillator is one third of its amplitude, the ratio of total energy to the kinetic energy is x8\frac{x}{8}, where x=x = _______
  3. Question 3

    This type asked 6 times: 25 Jul 2022, 28 Jul 2022, 25 Jan 2023, 30 Jan 2024, 1 Feb 2024, 5 Apr 2024. This one: 5 Apr 2024 See all 6 of this type

    15
    A simple pendulum doing small oscillations at a place RR height above earth surface has time period of T1=4 sT_{1}= 4\text{ }s. T2T_{2} would be it's time period if it is brought to a point which is at a height 2R2R from earth surface. Choose the correct relation [R=\lbrack R = radius of Earth]:

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  4. Question 4

    This type asked 5 times: 2021 Paper 13, 2021 Paper 19, 2021 Paper 21, 10 Apr 2023, 2 Apr 2025. This one: 2 Apr 2025 See all 5 of this type

    9
    A particle is subjected two simple harmonic motions as : x1=7sin⁡5t cmx_{1}=\sqrt{7}\sin 5t\ cm and x2=27sin⁡(5t+π3)cmx_{2}= 2\sqrt{7}\sin\left( 5t+\frac{\pi}{3} \right)cm where x is displacement and tt is time in seconds. The maximum acceleration of the particle is x×10−2 ms−2x \times10^{- 2}{\text{ }ms}^{- 2}. The value of x is :

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  5. Question 5

    This type asked 5 times: 2021 Paper 2, 2021 Paper 4, 24 Jan 2023, 31 Jan 2023, 6 Apr 2023. This one: 6 Apr 2023 See all 5 of this type

    18
    A mass mm is attached to two springs as shown in figure. The spring constants of two springs are K1K_{1} and K2K_{2}. For the frictionless surface, the time period of oscillation of mass mm is

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  6. Question 6

    This type asked 4 times: 27 Jun 2022, 25 Jan 2023, 29 Jan 2024, 6 Apr 2026 S1. This one: 6 Apr 2026 S1 See all 4 of this type

    12
    A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec . the time required by it to move from x=Ax=A to x=A2x=\frac{A}{\sqrt{2}} is ____\_\_\_\_ sec.

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  7. Question 7

    This type asked 4 times: 2021 Paper 3, 2021 Paper 13, 29 Jun 2022, 23 Jan 2026 S1. This one: 23 Jan 2026 S1 See all 4 of this type

    6
    A simple pendulum of string length 30 cm performs 20 oscillations in 10s. The length of the string required for the pendulum to perform 40 oscillations in the same time duration is ____\_\_\_\_ cm. [Assume that the mass of the pendulum remains same.]

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  8. Question 8

    This type asked 4 times: 24 Jan 2023, 30 Jan 2023, 1 Feb 2024, 9 Apr 2024. This one: 9 Apr 2024 See all 4 of this type

    112
    A particle of mass 0.50 kg0.50\text{ }kg executes simple harmonic motion under force F=−50(Nm−1)xF = - 50\left( Nm^{- 1} \right)x. The time period of oscillation is x35 s\frac{x}{35}\text{ }s. The value of xx is_______ (Given π=227\pi=\frac{22}{7} )
  9. Question 9

    Asked 3 times: 2021 Paper 2, 2021 Paper 26, 26 Jul 2022 See all 3 times it was asked

    12
    When a particle executes simple Harmonic motion, the nature of graph of velocity as function of displacement will be:

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  10. Question 10

    This type asked 3 times: 2021 Paper 25, 24 Jan 2026 S1, 8 Apr 2026 S2. This one: 8 Apr 2026 S2 See all 3 of this type

    12
    The frequency of oscillation of a mass m suspended by spring is v1v_{1}. If the length of the spring is cut to half, the same mass oscillates with frequency v2v_{2}. The value of v2v1\frac{v_{2}}{v_{1}} is ____\_\_\_\_ .

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