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Rate of 2NOBr to 2NO + Br2 from k and the NOBr concentration

The same question, asked 2 times: 17 Apr 2026 S2*, 18 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    17 Apr 2026 S2

    28
    For the reaction 2NOBr(g)→2NO(g)+Br2(g)\mathrm{2NOBr_{(g)} \rightarrow 2NO_{(g)} + Br_{2(g)}} rate law is r=k[NOBr]2r = k[\mathrm{NOBr}]^2, if rate constant is 1.62 mol dm−3 s−11.62\ \mathrm{mol\,dm^{-3}\,s^{-1}} and concentration of NOBr is 2×10−3 mol L−12 \times 10^{-3}\ \mathrm{mol\,L^{-1}}. What is the rate of reaction ?

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  2. Question 2

    18 Apr 2026 S1

    28
    For the reaction 2NOBr(g)⟶2NO(g)+Br2(g)\mathrm{2NOBr_{(g)} \longrightarrow 2NO_{(g)} + Br_{2(g)}}, rate law is r=k[NOBr]2r = k[\mathrm{NOBr}]^2. Rate constant is 1.62 M s−11.62\ \mathrm{M\,s^{-1}} and concentration of NOBr is 5×10−35 \times 10^{-3} M, What is rate of reaction?

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