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Rate constant from the rate when rate = k[A]^2[B]

The same question, asked 3 times: 10 May 2023 S2*, 9 May 2024 S1*, 13 May 2024 S2. Every wording below, oldest first.

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  1. Question 1

    10 May 2023 S2

    73
    For the reaction A+B→A + B \rightarrow product, rate law equation is rate =k[A]2[B]= k[A]^2[B]. If rate of reaction is 0.22 mol L−1 s−10.22\,\text{mol}\,\text{L}^{-1}\,\text{s}^{-1}, calculate rate constant. [A]=1 mol L−1[A] = 1\,\text{mol}\,\text{L}^{-1}, [B]=0.25 mol L−1[B] = 0.25\,\text{mol}\,\text{L}^{-1}

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  2. Question 2

    9 May 2024 S1

    80
    The rate of reaction, A+B→A+B\to product, is 1.8×10−2 mol dm−3 s−11.8\times10^{-2}\,mol\,dm^{-3}\,s^{-1}. Calculate the rate constant if the reaction is second order in A and first order in B ([A]=0.2 M;[B]=0.1 M[A]=0.2\,M; [B]=0.1\,M)

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  3. Question 3

    13 May 2024 S2

    95
    For the reaction 2A+2B→2C+D2\text{A}+2\text{B}\to2\text{C}+\text{D}, the rate law is expressed as rate =k[A]2[B]=k[\text{A}]^2[\text{B}]. Calculate the rate constant if rate of reaction 0.24 mol dm−3 s−10.24\ \text{mol dm}^{-3}\ \text{s}^{-1} [A]=0.5 M[\text{A}]=0.5\ \text{M} and [B]=0.2 M][\text{B}]=0.2\ \text{M}]

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