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Rate of reaction from k = 6.25 (or 6.0), [A] = 1 M and [B] = 0.2 M

The same question, asked 4 times: 11 May 2023 S2*, 12 May 2024 S2*, 25 Apr 2025 S1*, 16 Apr 2026 S2. Every wording below, oldest first.

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  1. Question 1

    11 May 2023 S2

    78
    Rate law for a reaction is r=k[A]2[B]r = k[A]^2[B]. If rate constant is 6.25 mol−2dm6s−16.25\ \text{mol}^{-2}\text{dm}^6\text{s}^{-1}, what is the rate of reaction when [A]=1 mol dm−3[A] = 1\ \text{mol dm}^{-3} and [B]=0.2 mol dm−3[B] = 0.2\ \text{mol dm}^{-3}?

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  2. Question 2

    12 May 2024 S2

    84
    The rate law for the reaction A+B→CA + B \rightarrow C at 25°C25°C is given by rate =k[A][B]2= k[A][B]^2. Calculate the rate of reaction if rate constant at same temperature is 6.256.25 mol⁻² dm⁶ s⁻¹, [A]=1[A] = 1 M, [B]=0.2[B] = 0.2 M

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  3. Question 3

    25 Apr 2025 S1

    82
    If r=k[A]2[ B]r = k\lbrack A\rbrack^{2}\lbrack\text{ }B\rbrack is rate law equation for reaction A+B→CA + B \rightarrow C, at [A]=1M\lbrack A\rbrack = 1M and, [B]=0.2M\lbrack B\rbrack = 0.2M, Calculate rate of reaction if rate constant is 6.25M−2 s−16.25M^{- 2}{\text{ }s}^{- 1}.

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  4. Question 4

    16 Apr 2026 S2

    28
    The rate law for the reaction A+B→PA + B \rightarrow P is found to be rate =k[A]2[B]= k[A]^2[B]. The rate constant of the reaction at 300 K is 6.0 M−2s−16.0\ \mathrm{M^{-2}s^{-1}}. Calculate the rate of the reaction when [A]=1[A] = 1 M and [B]=0.2[B] = 0.2 M

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