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Potential of a single electrode at a given ion concentration from its standard potential (Nernst)

The same question, asked 9 times: 21 Apr 2025 S1*, 21 Apr 2025 S2*, 22 Apr 2025 S1*, 22 Apr 2025 S2*, 25 Apr 2025 S1*, 26 Apr 2025 S1*, 11 Apr 2026 S2*, 20 Apr 2026 S2*, 13 May 2026 S2. Every wording below, oldest first.

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  1. Question 1

    21 Apr 2025 S1

    85
    If E∘(Mg+2 (aq)∣Mg(s))=−2⋅37 VE^{\circ}\left( Mg^{+ 2}\ _{(aq)}\mid Mg_{(s)} \right)= - 2 \cdot 37\text{ }V. What is potential for Mg(s)→Mg+2(0.1M)+2e−Mg_{(s)}\rightarrow Mg^{+ 2}(0.1M) + 2e^{-} at 298 K ?

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  2. Question 2

    21 Apr 2025 S2

    62
    If E∘(Ag+ (aq)∣Ag(s))=+0.80 VE^{\circ}\left( Ag^{+}\ _{(aq)}\mid Ag_{(s)} \right)= + 0.80\text{ }V What is potential developed for Ag(s)⟶Ag+1(0.01M)+e−Ag(s) \longrightarrow Ag^{+ 1}(0.01M) +e^{-}at 298 K ?

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  3. Question 3

    22 Apr 2025 S1

    100
    If E∘(Mg(aq)+2∣Mg(s))=−2.37 VE^{\circ}\left( Mg_{(aq)}^{+ 2}\mid Mg_{(s)} \right)= - 2.37\text{ }V. What is potential for Mg(s)⟶Mg+2(0.01M)+2e−Mg_{(s)}\longrightarrow Mg^{+ 2}(0.01M) + 2e^{-}at 298 K ?

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  4. Question 4

    22 Apr 2025 S2

    63
    If E∘(Al(aq)+3∣Al(s))=−1.66 VE^{\circ}\left( Al_{(aq)}^{+ 3}\mid Al_{(s)} \right)= - 1.66\text{ }V. What is potential of Al(s)⟶Al+3(0⋅1M)+3e−Al_{(s)}\longrightarrow Al^{+ 3}(0 \cdot 1M) + 3e^{-}at 298 K ?

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  5. Question 5

    25 Apr 2025 S1

    94
    If E∘(Zn(aq)+2∣Zn(s))=−0.76 VE^{\circ}\left( Zn_{(aq)}^{+ 2}\mid Zn_{(s)} \right)= - 0.76\text{ }V. Calculate potential for Zn(s)→Zn+2(0.01M)+2e−Zn_{(s)}\rightarrow Zn^{+ 2}(0.01M) + 2e^{-}at 298 K .

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  6. Question 6

    26 Apr 2025 S1

    99
    If E∘(Cu(aq)+2∣Cu(s))=+0.34 VE^{\circ}\left( Cu_{(aq)}^{+ 2}\mid Cu_{(s)} \right)= + 0.34\text{ }V. What is potential for Cu(s)→Cu(aq)+2(0.1M)+2e−Cu_{(s)}\rightarrow Cu_{(aq)}^{+ 2}(0.1M) + 2e^{-}at 298 K ?

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  7. Question 7

    11 Apr 2026 S2

    24
    The standard potential of Cu+2/Cu\mathrm{Cu^{+2}/Cu} is 0.340.34 V at 298298 K. Calculate its potential at the same temperature when the Cu+2\mathrm{Cu^{+2}} ion concentration is 0.10.1 M.

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  8. Question 8

    20 Apr 2026 S2

    25
    Determine the electrode potential of Sn2+(0.01M) ∣ Sn(s)\mathrm{Sn^{2+}(0.01M)\,|\,Sn(s)} at 25 ∘C25\ ^\circ\mathrm{C} if ESn∘E^\circ_{\mathrm{Sn}} is −0.136-0.136 V.

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  9. Question 9

    13 May 2026 S2

    28
    Calculate the electrode potential of Mg2+/Mg\mathrm{Mg^{2+}/Mg} electrode having 0.010.01 M concentration of Mg2+\mathrm{Mg^{2+}} (E∘Mg2+/Mg=−2.36(E^\circ\mathrm{Mg^{2+}/Mg} = -2.36 V).

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