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Volume of a unit cell from the molar mass and density

This type of question, asked 7 times: 2 May 2023 S1, 3 May 2023 S2, 9 May 2023 S1, 10 May 2023 S1, 13 May 2024 S2, 14 May 2024 S1, 11 Apr 2026 S1. All 7 questions below, oldest first.

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  1. Question 1

    2 May 2023 S1

    66
    Calculate the volume of unit cell of an element having molar mass 2727 g mol−1^{-1} that forms fcc unit cell. ρ⋅NA=16.0×1023\rho \cdot N_A = 16.0 \times 10^{23} g cm−3^{-3} mol−1^{-1}

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  2. Question 2

    3 May 2023 S2

    92
    Calculate the volume of unit cell of an element having molar mass 63.5 g mol−163.5\text{ g mol}^{-1} that forms fcc structure [ϱ×NA=5.5×1024 g cm−3 mol−1][\varrho\times N_A = 5.5\times10^{24}\text{ g cm}^{-3}\text{ mol}^{-1}]

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  3. Question 3

    9 May 2023 S1

    54
    Calculate the volume of unit cell when metal having density 1 g cm−31\,\text{g\,cm}^{-3} and molar mass 23 g mol−123\,\text{g\,mol}^{-1} crystallises to form bcc structure.

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  4. Question 4

    10 May 2023 S1

    52
    Calculate the volume of unit cell if an element having molar mass 92 g mol−192\,\text{g mol}^{-1} forms bcc structure (ϱ×NA=5.0×1024 g cm−3 mol−1)(\varrho\times N_A=5.0\times10^{24}\,\text{g cm}^{-3}\text{ mol}^{-1})

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  5. Question 5

    13 May 2024 S2

    97
    Calculate the volume of unit cell if an element having molar mass 180 g mol−1180\ \text{g mol}^{-1} forms fcc unit cell. [d×NA=120×1021 g cm−3 mol−1d\times N_A=120\times10^{21}\ \text{g cm}^{-3}\ \text{mol}^{-1}]

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  6. Question 6

    14 May 2024 S1

    63
    Calculate the volume of unit cell if an element having molar mass 56 g mol−156\,\text{g mol}^{-1} forms bcc unit cells. [ρ⋅NA=4.8×1024 g cm−3 mol−1\rho\cdot N_A=4.8\times10^{24}\,\text{g cm}^{-3}\,\text{mol}^{-1}]

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  7. Question 7

    11 Apr 2026 S1

    17
    In a cubic unit cell of an ionic compound, the eight corners are occupied by anions and cations at the center of the cube. Calculate the volume of the unit cell if density of the unit cell is 4 g cm−34\ \mathrm{g\,cm^{-3}}. [Molar mass of compound =168.6 g mol−1= 168.6\ \mathrm{g\,mol^{-1}} and NA=6.022×1023N_A = 6.022 \times 10^{23}]

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