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Molar mass of a solute from the elevation of boiling point of its solution

The same question, asked 7 times: 2 May 2023 S2*, 10 May 2023 S2*, 9 May 2024 S1*, 11 Apr 2026 S2*, 13 Apr 2026 S1*, 17 Apr 2026 S1*, 14 May 2026 S2. Every wording below, oldest first.

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  1. Question 1

    2 May 2023 S2

    100
    Calculate the molar mass of a non-volatile solute when 5 g of it is dissolved in 50 g solvent, boils at 119.6∘C119.6^\circ\text{C}. (Kb=3.2 K kg mol−1K_b = 3.2\,\text{K kg mol}^{-1}, boiling point of pure solvent =118∘C= 118^\circ\text{C})

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  2. Question 2

    10 May 2023 S2

    99
    Calculate molar mass of nonvolatile solute if a solution containing 0.35 g solute in 100 g water has boiling point elevation 0.01 K. (Kb=0.50 K kg mol−1K_b = 0.50\,\text{K}\,\text{kg}\,\text{mol}^{-1})

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  3. Question 3

    9 May 2024 S1

    69
    A solution of non-volatile solute is obtained by dissolving 3.5 g in 100 g solvent and has boiling point elevation 0.35 K. Calculate the molar mass of solute (molal elevation constant =2.5 K kg mol−1=2.5\,K\,kg\,mol^{-1})

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  4. Question 4

    11 Apr 2026 S2

    22
    A solution of 50g of solute 'X' is dissolved in 150150 g of 'Y' solvent boils at 357.27357.27 K. What is the molar mass of solute? (Given KbK_b and boiling point pure solvent is 2.772.77 K kg/mol and 350.06350.06 K respectively.)

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  5. Question 5

    13 Apr 2026 S1

    20
    2 g nonelectrolyte solute when dissolved in 50 g water increases its boiling point by 0.13 K. Calculate the molar mass of solute if molal elevation constant of water is 0.52 K kg mol−1\mathrm{mol^{-1}}

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  6. Question 6

    17 Apr 2026 S1

    23
    Calculate the molar mass of nonvolatile solute when 4 g of it is dissolved in 100 g solvent that boils at 319.4 K [KbK_b = 2.4 K kg mol−1\mathrm{mol^{-1}}; B.P of pure solvent = 319 K]

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  7. Question 7

    14 May 2026 S2

    22
    A solution of 10.010.0 g of a nonvolatile, nonelectrolyte solute dissolved in 0.20.2 kg of benzene boils at 81.2∘C81.2^\circ\mathrm{C}. Calculate molar mass of the compound. (ebullioscopic constant for benzene =2.53= 2.53 K kg mol−1\mathrm{mol^{-1}} and boiling point of pure benzene =80.1∘C= 80.1^\circ\mathrm{C})

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