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Ideal gas equation PV = nRT: find the moles, pressure or temperature

This type of question, asked 5 times: 3 May 2023 S1, 15 May 2023 S2, 14 May 2024 S1, 13 Apr 2026 S1, 20 Apr 2026 S1. All 5 questions below, oldest first.

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  1. Question 1

    3 May 2023 S1

    76
    How many moles of dioxygen are present in 8.314×10−3 m38.314\times10^{-3}\ \text{m}^3 of it at 318 K having pressure 3.18×105 Nm−23.18\times10^5\ \text{Nm}^{-2}? [R=8.314 J K−1 mol−1R=8.314\ \text{J K}^{-1}\ \text{mol}^{-1}]

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  2. Question 2

    15 May 2023 S2

    64
    3.4 moles of an ideal gas occupies volume of 68 mL at 300 K. What would be the pressure of gas? R=8.314 J K−1 mol−1R = 8.314\text{ J K}^{-1}\text{ mol}^{-1}

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  3. Question 3

    14 May 2024 S1

    58
    Find the temperature in degree Celsius if volume and pressure of 2 mole ideal gas is 20 dm320\,\text{dm}^3 and 4.926 atmosphere respectively. (R=0.0821 dm3 atm K−1 mol−1R=0.0821\,\text{dm}^3\,\text{atm}\,\text{K}^{-1}\,\text{mol}^{-1})

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  4. Question 4

    13 Apr 2026 S1

    6
    Calculate the temperature of 2 moles of gas occupying a volume of 5.0 liters at 24.6 atmospheres? (R=0.0821(R = 0.0821 L atm K−1 mol−1)\mathrm{K^{-1}\,mol^{-1}})

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  5. Question 5

    20 Apr 2026 S1

    5
    Find the number of moles of CO2\mathrm{CO_2} present in a sample occuping 4×10−3 m34 \times 10^{-3}\ \mathrm{m^3} at 1.104×105 Nm−21.104 \times 10^5\ \mathrm{Nm^{-2}} pressure (R×T=2208 J mol−1)(R \times T = 2208\ \mathrm{J\,mol^{-1}})

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