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Day 10: MHT-CET Maths

5 questions. Try each one first, then open its answer.

  1. Question 1

    Mathematical Logic. This type asked 9 times: May 2022 S1, 9 May 2023 S1, 15 May 2023 S2, 19 Apr 2025 S1, 22 Apr 2025 S1, 25 Apr 2025 S2, 26 Apr 2025 S2, 20 Apr 2026 S1, 20 Apr 2026 S2. This one: 20 Apr 2026 S2 See all 9 of this type

    51
    The statement having truth value 'T' from the following is

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  2. Question 2

    Differentiation. This type asked 9 times: 10 May 2023 S1, 10 May 2023 S2, 15 May 2023 S1, 9 May 2024 S2, 10 May 2024 S2, 12 May 2024 S1, 13 May 2024 S2, 18 Apr 2026 S1, 19 Apr 2026 S2. This one: 19 Apr 2026 S2 See all 9 of this type

    74
    If 3y2−2xy−x=03y^2 - 2xy - x = 0, then the value of dydx\dfrac{dy}{dx} at y=2y = 2 is...

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  3. Question 3

    Vectors. This type asked 9 times: 2 May 2023 S2, 3 May 2023 S2, 9 May 2023 S1, 10 May 2023 S2, 9 May 2024 S2, 13 May 2024 S2, 25 Apr 2025 S1, 16 Apr 2026 S1, 18 Apr 2026 S2. This one: 18 Apr 2026 S2 See all 9 of this type

    93
    If aˉ⋅bˉ=β\bar{a}\cdot\bar{b} = \beta and aˉ×bˉ=cˉ\bar{a} \times \bar{b} = \bar{c} then aˉ=\bar{a} =

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  4. Question 4

    Differentiation. This type asked 9 times: 15 May 2023 S2, 16 May 2023 S1, 16 May 2023 S2, 9 May 2024 S1, 10 May 2024 S2, 20 Apr 2025 S1, 22 Apr 2025 S2, 13 Apr 2026 S1, 18 Apr 2026 S1. This one: 18 Apr 2026 S1 See all 9 of this type

    75
    If g(x)=(x2+2x+1)⋅f(x)g(x) = (x^2 + 2x + 1)\cdot f(x) such that f(0)=5f(0) = 5 and lim⁡x→0f(x)−5x=4\lim_{x \to 0}\dfrac{f(x) - 5}{x} = 4 then g′(0)=g'(0) =

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  5. Question 5

    Differentiation. This type asked 9 times: 3 May 2023 S2, 4 May 2023 S1, 11 May 2023 S1, 15 May 2023 S1, 11 May 2024 S2, 12 May 2024 S1, 13 May 2024 S2, 14 May 2024 S1, 17 Apr 2026 S1. This one: 17 Apr 2026 S1 See all 9 of this type

    72
    If y=[(x+1)(2x+1)(3x+1)……(nx+1)]4y = [(x + 1)(2x + 1)(3x + 1)\ldots\ldots(nx + 1)]^4, where n∈Nn \in N and dydx\dfrac{dy}{dx} at x=0x = 0 is 2k2k, then the value of kk is

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