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Day 18: MHT-CET Maths

5 questions. Try each one first, then open its answer.

  1. Question 1

    Trigonometric Functions. This type asked 7 times: 9 May 2024 S1, 14 May 2024 S2, 19 Apr 2025 S1, 26 Apr 2025 S2, 18 Apr 2026 S1, 20 Apr 2026 S1, 14 May 2026 S2. This one: 14 May 2026 S2 See all 7 of this type

    70
    The value of cot⁡−1(ab+1a−b)+tan⁡−1(b−cbc+1)+cot⁡−1(ac+1c−a)\cot^{-1}\left(\dfrac{ab + 1}{a - b}\right) + \tan^{-1}\left(\dfrac{b - c}{bc + 1}\right) + \cot^{-1}\left(\dfrac{ac + 1}{c - a}\right) is

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  2. Question 2

    Trigonometric Functions. This type asked 7 times: 3 May 2023 S1, 11 May 2024 S2, 20 Apr 2025 S1, 11 Apr 2026 S2, 16 Apr 2026 S2, 12 May 2026 S1, 14 May 2026 S2. This one: 14 May 2026 S2 See all 7 of this type

    53
    The number of solutions of cos⁡2x=cos⁡x\cos 2x = \cos x in the interval [0,2π][0, 2\pi] is

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  3. Question 3

    Line and Plane. This type asked 7 times: 4 May 2023 S2, 11 May 2023 S1, 10 May 2024 S2, 25 Apr 2025 S1, 11 Apr 2026 S1, 16 Apr 2026 S1, 14 May 2026 S1. This one: 14 May 2026 S1 See all 7 of this type

    95
    The distance of the point 2i^+j^−k^2\hat{i} + \hat{j} - \hat{k} from the plane rˉ⋅(i^−2j^+4k^)=9\bar{r}\cdot(\hat{i} - 2\hat{j} + 4\hat{k}) = 9, is

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  4. Question 4

    Differential Equations. This type asked 7 times: May 2021 S1, 9 May 2024 S1, 26 Apr 2025 S2, 16 Apr 2026 S1, 18 Apr 2026 S2, 13 May 2026 S1, 13 May 2026 S2. This one: 13 May 2026 S2 See all 7 of this type

    86
    The differential equation of all parabolas which have 4a4a as latus rectum and whose axis is parallel to the X-axis is 2ad2ydx2+(dydx)k=02a\dfrac{d^2y}{dx^2} + \left(\dfrac{dy}{dx}\right)^k = 0, then the value of kk is...

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  5. Question 5

    Mathematical Logic. This type asked 7 times: 4 May 2023 S2, 9 May 2024 S1, 10 May 2024 S2, 25 Apr 2025 S1, 15 Apr 2026 S1, 19 Apr 2026 S2, 12 May 2026 S1. This one: 12 May 2026 S1 See all 7 of this type

    66
    If the truth values of p,q,r,sp, q, r, s are respectively T,F,F,TT, F, F, T then the truth values of the compound statements ∼(p→∼q)\sim(p \to \sim q) and (∼r∧s)→(p∧∼q)(\sim r \wedge s) \to (p \wedge \sim q) are respectively ... and .....

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