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Day 277: MHT-CET Maths

5 questions. Try each one first, then open its answer.

  1. Question 1

    Differentiation. Asked once: 23 Apr 2025 S1 (same type asked 8 times) See all 8 of this type

    135
    If y=tan⁡−1[4sin⁡2xcos⁡2x−6sin⁡2x]y=\tan^{- 1}\left\lbrack \frac{4\sin2x}{\cos2x- 6\sin^{2}x} \right\rbrack, then dy dx\frac{dy}{\text{ }dx} at x=0x= 0 is

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  2. Question 2

    Trigonometric Functions. Asked once: 22 Apr 2025 S2 (same type asked 8 times) See all 8 of this type

    132
    The number of solutions of tan⁡−1(x+2x)−tan⁡−1(4x)−tan⁡−1(x−2x)=0\tan^{- 1}\left( x+\frac{2}{x} \right)-\tan^{- 1}\left( \frac{4}{x} \right)-\tan^{- 1}\left( x-\frac{2}{x} \right)= 0 are

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  3. Question 3

    Linear Programming. Asked once: 19 Apr 2025 S2 (same type asked 8 times) See all 8 of this type

    121
    The feasible region for the constraints x−2⩽y,x⩾y−1,x⩾2,y⩽4,x,y⩾0x- 2 \leqslant y,x\geqslant y- 1,x\geqslant 2,y\leqslant 4,x,y\geqslant 0, is____.\_\_\_\_.

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  4. Question 4

    Differential Equations. Asked once: 16 May 2023 S1 (same type asked 8 times) See all 8 of this type

    124
    Let y=y(x)y = y(x) be the solution of the differential equation xlog⁡x dydx+y=2xlog⁡x  (x≥1)x\log x\,\frac{dy}{dx} + y = 2x\log x\; (x \geq 1), then y(e)y(e) is equal to

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  5. Question 5

    Mathematical Logic. Asked once: 13 May 2026 S2 (same type asked 7 times) See all 7 of this type

    67
    The negation of the contrapositive of the statement (p∨q)→r(p \vee q) \to r is logically equivalent to..

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