Given mean and variance of a binomial: find n and p, then a probability

1. A.
   17
2. B.
   121
3. C.
   1
4. D.
   137

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1. A.
   $\frac{1}{16}$
2. B.
   $\frac{9}{16}$
3. C.
   $\frac{3}{4}$
4. D.
   $\frac{15}{16}$

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1. A.
   $\frac{5}{16}$
2. B.
   $\frac{11}{16}$
3. C.
   $\frac{12}{16}$
4. D.
   $\frac{15}{16}$

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1. A.
   17
2. B.
   121
3. C.
   136
4. D.
   137

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1. A.
   $0.0625$
2. B.
   $0.2500$
3. C.
   $0.3125$
4. D.
   $0.6875$

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1. A.
   $P(X = 0) = 3P(X = 4)$
2. B.
   $P(X = 1) = 2P(X = 2)$
3. C.
   $P(X = 3) = 3P(X = 4)$
4. D.
   $3P(X = 0) = 4P(X = 1)$

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1. A.
   $\dfrac{15}{16}$
2. B.
   $\dfrac{1}{16}$
3. C.
   $\dfrac{1}{4}$
4. D.
   $\dfrac{11}{16}$

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