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Integral of x^2 cos x/(1 + e^x) from -pi/2 to pi/2

The same question, asked 2 times: 9 May 2023 S1*, 15 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    9 May 2023 S1

    136
    The value of I=∫−π/2π/2x2cos⁡x1+e−x dxI = \int_{-\pi/2}^{\pi/2}\frac{x^2\cos x}{1+e^{-x}}\,dx is equal to

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  2. Question 2

    15 Apr 2026 S1

    82
    The value of the integral ∫−π/2π/2(x2cos⁡x1+ex)dx\displaystyle\int_{-\pi/2}^{\pi/2}\left(\dfrac{x^2\cos x}{1 + e^x}\right)dx is equal to (π2A)−B\left(\dfrac{\pi^2}{A}\right) - B. Then (AB)=\left(\dfrac{A}{B}\right) =

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