Integral of 1/((x + p) sqrt(x + 1)) by putting x + 1 = t^2
The same question, asked 2 times: 20 Apr 2025 S2*, 12 May 2026 S2. Every wording below, oldest first.
Try each one first, then open its answer.
Question 1
20 Apr 2025 S2
121∫03(x+2)x+1dx=
Tap an option to check your answer.
Question 2
12 May 2026 S2
81The value of the integral ∫815(x−3)x+1dx is....
Tap an option to check your answer.