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Integral from 0 to 1 of an inverse trigonometric function, by parts

This type of question, asked 2 times: 10 May 2024 S2, 26 Apr 2025 S1. All 2 questions below, oldest first.

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  1. Question 1

    10 May 2024 S2

    148
    ∫01cos⁡−1x dx=\displaystyle\int_0^1 \cos^{-1}x\,dx=

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  2. Question 2

    26 Apr 2025 S1

    117
    ∫01tan⁡−1x dx=\int_{0}^{1} \tan^{- 1}x\text{ }dx=

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