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Solve x dy/dx = y(log y - log x + 1)

The same question, asked 2 times: 2 May 2023 S1, 23 Apr 2025 S1. Every wording below, oldest first.

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  1. Question 1

    2 May 2023 S1

    132
    If xdydx=y(log⁡y−log⁡x+1)x\dfrac{dy}{dx} = y(\log y - \log x + 1), then general solution of this equation is

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  2. Question 2

    23 Apr 2025 S1

    115
    If x dy dx=y(log⁡y−log⁡x+1)x\frac{\text{ }dy}{\text{ }dx}=y(\log y- \log x+ 1), then the solution of the equation is

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