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Where [x(x - 2)]^2 is increasing

The same question, asked 2 times: May 2021 S1, 26 Apr 2025 S2. Every wording below, oldest first.

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  1. Question 1

    May 2021 S1

    139
    If y=p[x(x−2)]2y = p[x(x-2)]^2 is an increasing function, then the value of xx is

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  2. Question 2

    26 Apr 2025 S2

    106
    The function f(x)=[x(x−2)]2f(x) = \lbrack x(x- 2)\rbrack^{2} is increasing in the set

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