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General solution of a linear equation dy/dx + Py = Q

This type of question, asked 11 times: 10 May 2023 S1, 10 May 2024 S2, 11 May 2024 S2, 20 Apr 2025 S1, 22 Apr 2025 S1, 26 Apr 2025 S2, 15 Apr 2026 S1, 18 Apr 2026 S1, 19 Apr 2026 S2, 20 Apr 2026 S2, 15 May 2026 S2. All 11 questions below, oldest first.

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  1. Question 1

    10 May 2023 S1

    118
    If cos⁡xdydx−ysin⁡x=6x,  0<x<π2\cos x\frac{dy}{dx}-y\sin x=6x,\;0<x<\frac{\pi}{2}, then general solution of the differential equation is

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  2. Question 2

    10 May 2024 S2

    141
    The general solution of the differential equation dydx+3x21+x3y=1x3+1\dfrac{dy}{dx}+\dfrac{3x^2}{1+x^3}y=\dfrac{1}{x^3+1} is

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  3. Question 3

    11 May 2024 S2

    135
    The solution of the differential equation dydx+yx=sin⁡x\frac{dy}{dx}+\frac{y}{x}=\sin x is

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  4. Question 4

    20 Apr 2025 S1

    101
    The general solution of x(x−1)dy dx=x3(2x−1)+(x−2)yx(x- 1)\frac{dy}{\text{ }dx}=x^{3}(2x- 1) + (x- 2)y is

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  5. Question 5

    22 Apr 2025 S1

    118
    If y+ddx(xy)=x(sin⁡x+log⁡x)y+\frac{d}{dx}(xy) =x(\sin x+ \log x) then

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  6. Question 6

    26 Apr 2025 S2

    120
    The solution of the differential equation (1+x)dy dx−xy=1−x(1 +x)\frac{dy}{\text{ }dx}-xy= 1 -x is

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  7. Question 7

    15 Apr 2026 S1

    87
    The solution of the differential equation x2dydx−xy=1x^2\dfrac{dy}{dx} - xy = 1 is...

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  8. Question 8

    18 Apr 2026 S1

    87
    The general solution of the differential equation xsin⁡xdydx+(xcos⁡x+sin⁡x)y=sin⁡xx\sin x\dfrac{dy}{dx} + (x\cos x + \sin x)y = \sin x is

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  9. Question 9

    19 Apr 2026 S2

    85
    If the solution of the differential equation (1+x3)dydx+6x2y=1+x2(1 + x^3)\dfrac{dy}{dx} + 6x^2y = 1 + x^2 is y=1(1+x3)s[x+xpp+xqq+xrr+c]y = \dfrac{1}{(1 + x^3)^s}\left[x + \dfrac{x^p}{p} + \dfrac{x^q}{q} + \dfrac{x^r}{r} + c\right], then the LCM of p,q,rp, q, r and ss is...

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  10. Question 10

    20 Apr 2026 S2

    86
    The general solution of the differential equation dydx+yx=x2+5\dfrac{dy}{dx} + \dfrac{y}{x} = x^2 + 5 is ....

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  11. Question 11

    15 May 2026 S2

    87
    The general solution of the differential equation (x+1)dydx−y=ex(x+1)2(x + 1)\dfrac{dy}{dx} - y = e^x(x + 1)^2 is given by:

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