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x^2 + y^2 = t + 1/t and x^4 + y^4 = t^2 + 1/t^2: find dy/dx

The same question, asked 2 times: 11 May 2023 S1, 9 May 2024 S1. Every wording below, oldest first.

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  1. Question 1

    11 May 2023 S1

    121
    If x2+y2=t+1tx^2 + y^2 = t + \frac{1}{t}, x4+y4=t2+1t2x^4 + y^4 = t^2 + \frac{1}{t^2}, then dydx=\frac{dy}{dx} =

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  2. Question 2

    9 May 2024 S1

    102
    If x2+y2=t+1tx^2+y^2=t+\frac{1}{t} and x4+y4=t2+1t2x^4+y^4=t^2+\frac{1}{t^2}, then dydx\frac{dy}{dx} is equal to

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