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y^(1/m) + y^(-1/m) = 2x: find (x^2 - 1)(dy/dx)^2

The same question, asked 2 times: May 2022 S1, 16 Apr 2026 S1. Every wording below, oldest first.

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  1. Question 1

    May 2022 S1

    140
    If (y1/m+y−1/m)=2x\left(y^{1/m} + y^{-1/m}\right) = 2x, x≠1x \neq 1, then (x2−1) ⁣(dydx)2\left(x^2-1\right)\!\left(\frac{dy}{dx}\right)^2 is equal to

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  2. Question 2

    16 Apr 2026 S1

    72
    If y1m+y−1m=2xy^{\frac{1}{m}} + y^{\frac{-1}{m}} = 2x , then (x2−1)y12=(x^2 - 1)y_1^2 =

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